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Proof step 1 from proof Del-at-entries (conclusion)

⊦ (entries -- str0)[str] = (str ≠ str0 ⊃ entries[str];(∅)[str])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ (entries -- str0)[str] = (str ≠ str0 ⊃ entries[str];(∅)[str0])

Rule argument

Additional information