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Proof step 2 from proof Insert-size (previous step)

⊦ #(ls ++ alink) = # ls + 1, alink ∈ ls

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)% ⊦ ¬ alink ∈ ls → #(ls ++ alink) = # ls + 1; (s)