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Proof step 25 from proof afs-cons-mkdir-ino (previous step)

⊦ ¬ ino ∈ dirs ∧ ino ≠ 0 → links(ino0, (dirs ++ ino)[ino, mkdir(m, md, n, n0, ∅)]) = links(ino0, dirs)

A spec-lemma