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Proof step 12 from proof afs-cons-rename-dir-dentry (previous step)

dirs[dirs[m].entries[str]].entries = ∅, old_parent_inode.nlink = dirs[old_parent_inode.ino].nlink, old_parent_inode.nsubdirs = dirs[old_parent_inode.ino].nsubdirs, old_parent_inode.size = dirs[old_parent_inode.ino].size, boolvar, m0 = dirs[m].nlink, m1 = dirs[m].nsubdirs, m2 = dirs[m].size, new_child_inode = mkinode(dirs[m].entries[str], md, true, dirs[dirs[m].entries[str]].nlink, dirs[dirs[m].entries[str]].nsubdirs, dirs[dirs[m].entries[str]].size), new_dent = mkdentry(str, dirs[m].entries[str]), new_parent_inode = mkinode(m, md1, boolvar, m0, m1, m2), old_child_inode = mkinode (dirs[old_parent_inode.ino].entries[str0], md0, true, dirs[dirs[old_parent_inode.ino].entries[str0]].nlink, dirs[dirs[old_parent_inode.ino].entries[str0]].nsubdirs, dirs[dirs[old_parent_inode.ino].entries[str0]].size), old_dent = mkdentry(str0, dirs[old_parent_inode.ino].entries[str0]), old_parent_inode.directory, afs-cons(dirs, files), old_parent_inode.ino ∈ dirs, m ∈ dirs, dirs[old_parent_inode.ino].entries[str0] ∈ dirs, dirs[m].entries[str] ∈ dirs, str0 ∈ dirs[old_parent_inode.ino].entries, str ∈ dirs[m].entries, m = old_parent_inode.ino → md1 = old_parent_inode.meta, links(old_parent_inode.ino, dirs) ≠ ∅ ∨ old_parent_inode.ino = ROOT_INO, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO ⊦ ⟪afs_rename#(; old_parent_inode, new_parent_inode, old_child_inode, new_child_inode, old_dent, new_dent, err, dirs, files; asynced)⟫ afs-cons(dirs, files), dirs[m].entries[str] = ROOT_INO

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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