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Proof step 366 from proof afs-cons-rename-dir-dentry (previous step)

dirs0[entries0[str0]] = mkdir(m3, md3, # links(entries0[str0], dirs0), m6, ∅), dirs0[m] = mkdir(m1, md1, # links(m, dirs0), m4, entries0), dirs = dirs0[m, mkdir(m1, md2, # links(m, dirs0), m4, entries0)], ino = inode.ino, inode = mkinode(entries0[str0], md, true, # links(entries0[str0], dirs0), m6, m3), afs-cons(dirs0, files), m ∈ dirs0, entries0[str0] ∈ dirs0, str0 ∈ entries0, links(m, dirs0) ≠ ∅ ∨ m = ROOT_INO ⊦ ⟪if ino ∈ dirs then dirs[ino].meta := inode.meta; new_child_inode := getinode(entries0[str0], dirs, files); old_parent_inode := (m ∈ dirs ⊃ mkinode(m, dirs[m].meta, true, dirs[m].nlink, dirs[m].nsubdirs, dirs[m].size) ;mkinode(m, files[m].meta, false, files[m].nlink, 0, files[m].size) ); new_parent_inode := (m ∈ dirs ⊃ mkinode(m, dirs[m].meta, true, dirs[m].nlink, dirs[m].nsubdirs, dirs[m].size) ;mkinode(m, files[m].meta, false, files[m].nlink, 0, files[m].size) ); err := ESUCCESS; asynced := ?⟫ afs-cons(dirs, files), entries0[str0] = ROOT_INO, ino ∈ files

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

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