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Proof step 400 from proof afs-cons-rename-dir-dentry (previous step)

dirs[m0] = mkdir(m1, md, # links(m0, dirs), m3, entries2), dirs[m] = mkdir(m2, md0, # links(m, dirs), m5, entries1), dirs[entries1[str]] = mkdir(m4, md4, # links(entries1[str], dirs), m7, ∅), dirs[entries2[str0]] = mkdir(m6, md3, # links(entries2[str0], dirs), m9, entries), entries1[str] ≠ ROOT_INO, afs-cons(dirs, files), m0 ∈ dirs, m ∈ dirs, entries2[str0] ∈ dirs, entries1[str] ∈ dirs, str0 ∈ entries2, str ∈ entries1, m = m0 → md1 = md2, links(m0, dirs) ≠ ∅ ∨ m0 = ROOT_INO, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO ⊦ ⟪fail#(; ; err); asynced := ?⟫ true

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 401:
dirs[entries2[str0]] = mkdir(m6, md3, # links(entries2[str0], dirs), m9, entries), dirs[entries1[str]] = mkdir(m4, md4, # links(entries1[str], dirs), m7, ∅), dirs[m] = mkdir(m2, md0, # links(m, dirs), m5, entries1), dirs[m0] = mkdir(m1, md, # links(m0, dirs), m3, entries2), afs-cons(dirs, files), str ∈ entries1, str0 ∈ entries2, entries1[str] ∈ dirs, entries2[str0] ∈ dirs, m ∈ dirs, m0 ∈ dirs, m = m0 → md1 = md2, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO, links(m0, dirs) ≠ ∅ ∨ m0 = ROOT_INO ⊦ ⟪choose err0 with ⌊err0⌋ in err := err0; asynced := ?⟫ true, entries1[str] = ROOT_INO

Rule argument

pos: right 1

Additional information

Used simplifier rules: fail#(; ; ERR){choose ERR0 with ⌊ERR0⌋ in ERR := ERR0};