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Proof step 265 from proof afs-cons-rename-dir-negdentry (previous step)

dirs[m] = mkdir(m1, md, # links(m, dirs), m3, entries2), dirs[m0] = mkdir(m2, md4, # links(m0, dirs), m5, entries1), dirs[entries2[str]] = mkdir(m4, md2, # links(entries2[str], dirs), m7, entries), afs-cons(dirs, files), str ∈ entries2, entries2[str] ∈ dirs, m ∈ dirs, m0 ∈ dirs, ¬ str0 ∈ entries1, m0 = m → md1 = md0, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO, links(m0, dirs) ≠ ∅ ∨ m0 = ROOT_INO ⊦ ⟪fail#(; ; err); asynced := ?⟫ true

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 266:
dirs[entries2[str]] = mkdir(m4, md2, # links(entries2[str], dirs), m7, entries), dirs[m0] = mkdir(m2, md4, # links(m0, dirs), m5, entries1), dirs[m] = mkdir(m1, md, # links(m, dirs), m3, entries2), afs-cons(dirs, files), m0 ∈ dirs, m ∈ dirs, entries2[str] ∈ dirs, str ∈ entries2, m0 = m → md1 = md0, links(m0, dirs) ≠ ∅ ∨ m0 = ROOT_INO, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO ⊦ ⟪choose err0 with ⌊err0⌋ in err := err0; asynced := ?⟫ true, str0 ∈ entries1

Rule argument

pos: right 1

Additional information

Used simplifier rules: fail#(; ; ERR){choose ERR0 with ⌊ERR0⌋ in ERR := ERR0};