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Proof step 124 from proof afs-cons-rename-file-negdentry (previous step)

files[entries1[str]] = mkfile(m3, md, # links(entries1[str], dirs0), content0), dirs0[m0] = mkdir(m1 + 1, md2, # links(m0, dirs0), m6, entries1), files[ino] = mkfile(m8, md3, # links(ino, dirs0), content), dirs0[ino] = mkdir(m11, md6, m12, m13, entries), afs-cons(dirs0, files), ino ∈ files, ROOT_INO ∈ dirs0, str ∈ entries1, entries1[str] ∈ files, m0 ∈ dirs0, links(m0, dirs0) ≠ ∅ ∨ m0 = ROOT_INO ⊦ # links(ino, dirs0) = # (entries1[str] = ino ⊃ (links(entries1[str], dirs0) -- mklink(m0, str)) ++ mklink(m0, str0);links(ino, dirs0)), ino ∈ dirs0, entries1[str] ∈ dirs0, str0 ∈ entries1

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Proof step 125:
dirs0[ino] = mkdir(m11, md6, m12, m13, entries), files[ino] = mkfile(m8, md3, # links(ino, dirs0), content), dirs0[m0] = mkdir(m1 + 1, md2, # links(m0, dirs0), m6, entries1), files[entries1[str]] = mkfile(m3, md, # links(entries1[str], dirs0), content0), entries1[str] = ino, afs-cons(dirs0, files), m0 ∈ dirs0, entries1[str] ∈ files, str ∈ entries1, ROOT_INO ∈ dirs0, ino ∈ files, links(m0, dirs0) ≠ ∅ ∨ m0 = ROOT_INO ⊦ # links(ino, dirs0) = # (entries1[str] = ino ⊃ (links(entries1[str], dirs0) -- mklink(m0, str)) ++ mklink(m0, str0);links(ino, dirs0)), str0 ∈ entries1, entries1[str] ∈ dirs0, ino ∈ dirs0

Rule argument

fma: entries1[str] = ino

Additional information

Used formulas: entries1[str] = ino