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Proof step 73 from proof afs-cons-rename-file-negdentry (previous step)

(m0 = m ⊃ mkdir(m2, md2, # links(m, dirs0), m5, entries1 -- str);mkdir(m7, md5, # links(m0, dirs0), m9, entries2)) = mkdir(m1, md4, m4, m6, entries0), dirs0[m0] = mkdir(m7, md5, # links(m0, dirs0), m9, entries2), files[entries1[str]] = mkfile(m3, md, # links(entries1[str], dirs0), content0), dirs0[m] = mkdir(m2 + 1, md2, # links(m, dirs0), m5, entries1), dirs = dirs0[m0, mkdir(m1 + 1, md4, m4, m6, entries0[str0, entries1[str]])] [m, (m = m0 ⊃ mkdir(m1 + 1, md4, m4, m6, entries0[str0, entries1[str]]);mkdir(m2, md2, # links(m, dirs0), m5, entries1 -- str)).meta:= md0 ], ino = inode.ino, inode = mkinode(m0, md1, true, # links(m0, dirs0), m9, m7), afs-cons(dirs0, files), ino ∈ files, m ∈ dirs0, m0 ∈ dirs0, entries1[str] ∈ files, str ∈ entries1, m0 = m → md1 = md0, links(m0, dirs0) ≠ ∅ ∨ m0 = ROOT_INO, links(m, dirs0) ≠ ∅ ∨ m = ROOT_INO ⊦ ⟪asynced := ?⟫ afs-cons(dirs, files[ino, files[ino].size:= inode.size][ino, files[ino, files[ino].size:= inode.size][ino].meta:= inode.meta]), str0 ∈ entries2, entries1[str] ∈ dirs0

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ mkinode(m, md, boolvar, m0, m1, m2).ino = m; (s)% ⊦ afs-cons(dirs, files) ∧ ino ∈ dirs → ¬ ino ∈ files; (s)