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Proof step 111 from proof inv-rmdir (previous step)

dirs[entries[str]] = mkdir(m0, md1, # links(entries[str], dirs), m2, ∅), dirs[m] = mkdir(m1, md2, # links(m, dirs), m4, entries), c_inode = mkinode(entries[str], md, true, # links(entries[str], dirs), m2, m0), dent = mkdentry(str, entries[str]), p_ino = p_inode.ino, p_inode = mkinode(m, md0, true, # links(m, dirs), m4, m1), afs-cons(dirs, files), pre-rmdir(p_inode, c_inode, dent, dirs, files), entries[str] ∈ dirs, str ∈ entries, m ∈ dirs, dirs[p_ino, dirs[p_ino].entries:= (dirs[p_ino].entries -- dent.name)][p_ino].size ≥ 1, dirs[p_ino, dirs[p_ino].entries:= (dirs[p_ino].entries -- dent.name)] [p_ino, dirs[p_ino, dirs[p_ino].entries:= (dirs[p_ino].entries -- dent.name)][p_ino] .size:= (dirs[p_ino, dirs[p_ino].entries:= (dirs[p_ino].entries -- dent.name)][p_ino].size - 1) ] [p_ino ] .nsubdirs ≥ 1, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO ⊦ entries[str] = ROOT_INO, dent.dentry?

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ valid-parent-ino(ino, dirs, files) ↔ ino ∈ dirs ∧ (links(ino, dirs) ≠ ∅ ∨ ino = ROOT_INO); (s)%⊦ valid-dentry(ino, dent, dirs, files) ↔ valid-parent-ino(ino, dirs, files) ∧ valid-ino(dent.ino, dirs, files) ∧ dent.name ∈ dirs[ino].entries ∧ dent.ino = dirs[ino].entries[dent.name] ∧ dent.dentry?; (s)% ⊦ mkdentry(str, m).ino = m; (s)%⊦ pre-rmdir(p_inode, c_inode, dent, dirs, files) ↔ dent.ino ≠ ROOT_INO ∧ valid-dentry(p_inode.ino, dent, dirs, files) ∧ dir-empty(dent.ino, dirs, files) ∧ valid-dir-inode(p_inode, dirs, files) ∧ valid-dir-inode(c_inode, dirs, files) ∧ c_inode.ino = dent.ino; (s)% ⊦ n ≥ m ↔ m ≤ n; (s)% ⊦ (ad.entries:= entries).nsubdirs = ad.nsubdirs; (s)% ⊦ (ad.size:= m).nsubdirs = ad.nsubdirs; (s)% ⊦ dirs[ino, ad][ino, ad0] = dirs[ino, ad0]; (s)% ⊦ (ad.entries:= entries).size = ad.size; (s)% ⊦ dirs[ino, ad][ino0] = (ino0 = ino ∧ ino ∈ dirs ⊃ ad;dirs[ino0]); (s)% ⊦ mkdentry(str, m).name = str; (s)% ⊦ mkinode(m, md, boolvar, m0, m1, m2).ino = m; (s)