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Proof step 129 from proof inv-rmdir (previous step)

# links(m, dirs) = m1, # links(entries[str], dirs) = dirs[entries[str]].nlink, dirs[entries[str]].entries = ∅, dirs[m] = mkdir(0, md2, m1, m2, entries), dirs[entries[str]] = mkdir(dirs[entries[str]].size, md1, dirs[entries[str]].nlink, dirs[entries[str]].nsubdirs, ∅), entries[str] = entries0[str], dirs[m] = mkdir(m0, md, m1, m2, entries0), m0 = 0, afs-cons(dirs, files), m ∈ dirs, str ∈ entries, entries[str] ∈ dirs, str ∈ entries0, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO ⊦ entries[str] = ROOT_INO

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 130:
# links(entries0[str], dirs) = dirs[entries0[str]].nlink, dirs[entries0[str]].entries = ∅, dirs[entries0[str]] = mkdir(dirs[entries0[str]].size, md1, dirs[entries0[str]].nlink, dirs[entries0[str]].nsubdirs, ∅), dirs[m] = mkdir(0, md, # links(m, dirs), m2, entries0), afs-cons(dirs, files), entries0[str] ∈ dirs, str ∈ entries0, m ∈ dirs, links(m, dirs) ≠ ∅ ∨ m = ROOT_INO ⊦ entries0[str] = ROOT_INO

Rule argument

Additional information

Used simplifier rules: ⊦ mkdir(m, md, m0, m1, entries) = mkdir(m2, md0, m3, m4, entries0) ↔ m = m2 ∧ md = md0 ∧ m0 = m3 ∧ m1 = m4 ∧ entries = entries0; (ws)%afs-cons-dir-nlink: ⊦ afs-cons(dirs, files) ∧ ino ∈ dirs ∧ dirs[ino] = mkdir(n0, md, n, n1, entries) → # links(ino, dirs) = n; (forward) from specification afs-base