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Proof step 135 from proof inv-rmdir (previous step)

dirs[entries0[str]] = mkdir(m0, md0, # links(entries0[str], dirs), m3, ∅), dirs[m] = mkdir(0, md, # links(m, dirs), m2, entries0), entries0[str] ∈ dirs, str ∈ entries0, m ∈ dirs, ROOT_INO ∈ dirs, ∀ ino. (ino ∈ dirs ∧ ino ≠ ROOT_INO ∧ links(ino, dirs) = ∅ → dirs[ino].entries = ∅) ∧ ( ino ∈ dirs → ¬ ino ∈ files ∧ dirs[ino].nlink = # links(ino, dirs) ∧ dirs[ino].nlink ≤ 1 ∧ dirs[ino].size = # dirs[ino].entries ∧ dirs[ino].nsubdirs = # subdirs(ino, dirs)) ∧ (ino ∈ files → ¬ ino ∈ dirs ∧ files[ino].nlink = # links(ino, dirs)) ∧ (∀ name. ino ∈ dirs ∧ name ∈ dirs[ino].entries → dirs[ino].entries[name] ∈ dirs ∨ dirs[ino].entries[name] ∈ files) ∧ (∀ n. ino ∈ files ∧ n ∈ files[ino].content → # files[ino].content[n] = VFS_PAGE_SIZE), links(m, dirs) ≠ ∅ ∨ m = ROOT_INO ⊦ entries0[str] = ROOT_INO

User applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: m abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ mkdir(m, md, m0, m1, entries).nsubdirs = m1; (s)% ⊦ mkdir(m, md, m0, m1, entries).size = m; (s)% ⊦ mkdir(m, md, m0, m1, entries).entries = entries; (s)% ⊦ # entries = 0 ↔ entries = ∅; (s)% ⊦ mkdir(m, md, m0, m1, entries).nlink = m0; (s)% ⊦ ¬ str ∈ ∅; (s) Used terms: m