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Proof step 51 from proof inv-rmdir (previous step)

(entries0[str] = m ⊃ mkdir(m3, md3, # links(entries0[str], dirs0), m0, entries0 -- str) ;mkdir(m1, md2, # links(entries0[str], dirs0), m4, ∅) ) = mkdir(m5, md1, m2 + 1, m7, entries), (ino = entries0[str] ⊃ mkdir(m5, md1, m2, m7, entries) ;(ino = m ⊃ mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str);mkdir(m9, md0, m10, m11, entries1)) ) = mkdir(m12, md4, m13, m14, entries2), dirs0[m] = mkdir(m3 + 1, md3, # links(m, dirs0), m0 + 1, entries0), dirs0[entries0[str]] = mkdir(m1, md2, # links(entries0[str], dirs0), m4, ∅), files[ino] = mkfile(m6, md, m8, content), dirs0[ino] = mkdir(m9, md0, m10, m11, entries1), afs-cons(dirs0, files), ROOT_INO ∈ dirs0, m ∈ dirs0, str ∈ entries0, entries0[str] ∈ dirs0, entries0[str] ∈ dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)], ino ∈ dirs0 → m10 = # links(ino, dirs0) ∧ # links(ino, dirs0) ≤ 1 ∧ m9 = # entries1 ∧ m11 = # subdirs(ino, dirs0), ino ∈ dirs0 ∧ name ∈ entries1 → entries1[name] ∈ dirs0 ∨ entries1[name] ∈ files, ino ∈ files → ¬ ino ∈ dirs0 ∧ m8 = # links(ino, dirs0), ino ∈ dirs0 ∧ ino ≠ ROOT_INO ∧ links(ino, dirs0) = ∅ → entries1 = ∅, links(m, dirs0) ≠ ∅ ∨ m = ROOT_INO ⊦ entries0[str] = ROOT_INO, ( ino ∈ dirs0 ∧ ino ≠ ROOT_INO ∧ links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)]) = ∅ → entries2 = ∅) ∧ ( ino ∈ dirs0 → m13 = # links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)]) ∧ # links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)]) ≤ 1 ∧ m12 = # entries2 ∧ m14 = # subdirs(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)])) ∧ ( ino ∈ files → ¬ ino ∈ dirs0 ∧ m8 = # links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)])) ∧ (ino ∈ dirs0 ∧ name ∈ entries2 → entries2[name] ∈ dirs0 ∨ entries2[name] ∈ files)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 52:
(ino = entries0[str] ⊃ mkdir(m5, md1, m2, m7, entries) ;(ino = m ⊃ mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str);mkdir(m9, md0, m10, m11, entries1)) ) = mkdir(m12, md4, m13, m14, entries2), (entries0[str] = m ⊃ mkdir(m3, md3, # links(entries0[str], dirs0), m0, entries0 -- str) ;mkdir(m1, md2, # links(entries0[str], dirs0), m4, ∅) ) = mkdir(m5, md1, m2 + 1, m7, entries), dirs0[ino] = mkdir(m9, md0, m10, m11, entries1), files[ino] = mkfile(m6, md, m8, content), dirs0[entries0[str]] = mkdir(m1, md2, # links(entries0[str], dirs0), m4, ∅), dirs0[m] = mkdir(m3 + 1, md3, # links(m, dirs0), m0 + 1, entries0), afs-cons(dirs0, files), str ∈ entries0, m ∈ dirs0, ROOT_INO ∈ dirs0, entries0[str] ∈ dirs0, ino ∈ dirs0 ∧ ino ≠ ROOT_INO ∧ links(ino, dirs0) = ∅ → entries1 = ∅, ino ∈ files → ¬ ino ∈ dirs0 ∧ m8 = # links(ino, dirs0), ino ∈ dirs0 ∧ name ∈ entries1 → entries1[name] ∈ dirs0 ∨ entries1[name] ∈ files, ino ∈ dirs0 → m10 = # links(ino, dirs0) ∧ # links(ino, dirs0) ≤ 1 ∧ m9 = # entries1 ∧ m11 = # subdirs(ino, dirs0), links(m, dirs0) ≠ ∅ ∨ m = ROOT_INO ⊦ entries0[str] = ROOT_INO, ( ino ∈ dirs0 ∧ ino ≠ ROOT_INO ∧ links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)]) = ∅ → entries2 = ∅) ∧ ( ino ∈ dirs0 → m13 = # links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)]) ∧ # links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)]) ≤ 1 ∧ m12 = # entries2 ∧ m14 = # subdirs(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)])) ∧ ( ino ∈ files → ¬ ino ∈ dirs0 ∧ m8 = # links(ino, dirs0[m, mkdir(m3, md3, # links(m, dirs0), m0, entries0 -- str)][entries0[str], mkdir(m5, md1, m2, m7, entries)])) ∧ (ino ∈ dirs0 ∧ name ∈ entries2 → entries2[name] ∈ dirs0 ∨ entries2[name] ∈ files)

Rule argument

Additional information

Used simplifier rules: ⊦ ino ∈ dirs[ino0, ad] ↔ ino ∈ dirs; (s)