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Proof step 8 from proof afs-cons-init (previous step)

⊦ 0 = # subdirs(ROOT_INO, (∅ ++ ROOT_INO)[ROOT_INO, mkdir(0, md, 0, 0, ∅)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ 0 = # subdirs(ROOT_INO, (∅ ++ ROOT_INO)[ROOT_INO, mkdir(0, md, 0, 0, ∅)]), subdirs(ROOT_INO, (∅ ++ ROOT_INO)[ROOT_INO, mkdir(0, md, 0, 0, ∅)]) = ∅

Rule argument

Additional information

Used simplifier rules: size-zero-01: ⊦ strings ≠ ∅ → # strings ≠ 0; (forward) from specification set-basic[dir-entries]%size-zero: ⊦ # strings ≠ 0 → strings ≠ ∅; (forward) from specification set-basic[dir-entries]