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Proof step 7 from proof afs-cons-links-empty (previous step)

dirs[ino] = mkdir(m1, md0, m2, m3, entries), files[ino] = mkfile(m, md, m0, content), afs-cons(dirs, files) ⊦ links(ino, dirs) = ∅ ↔ (ino ∈ dirs → m2 = 0) ∧ (ino ∈ files → m0 = 0), afs-cons(dirs, files) ∧ ¬ ino ∈ dirs ∧ ¬ ino ∈ files

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
files[ino] = mkfile(m, md, m0, content), dirs[ino] = mkdir(m1, md0, m2, m3, entries), afs-cons(dirs, files) ⊦ links(ino, dirs) = ∅ ↔ (ino ∈ dirs → m2 = 0) ∧ (ino ∈ files → m0 = 0), ¬ ino ∈ dirs ∧ ¬ ino ∈ files

Proof step 7 from proof afs-cons-links-empty (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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