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Proof step 2 from proof afs-cons-nlink0-notin (previous step)

afs-cons(dirs, files) ⊦ links(ino, dirs) = ∅, ino ∈ files, ino ∈ dirs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
afs-cons(dirs, files) ⊦ # links(ino, dirs) = 0, links(ino, dirs) = ∅, ino ∈ files, ino ∈ dirs

Rule argument

Additional information

Used simplifier rules: size-zero: ⊦ # ls ≠ 0 → ls ≠ ∅; (forward) from specification set-basic[alink-set]%size-zero-01: ⊦ ls ≠ ∅ → # ls ≠ 0; (forward) from specification set-basic[alink-set]