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Proof step 1 from proof afs-cons-non0 (conclusion)

⊦ afs-cons(dirs, files) ∧ ino ∈ dirs ∧ dirs[ino] = mkdir(n0, md, n, n1, entries) ∧ str ∈ entries → entries[str] ≠ 0

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information