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Proof step 3 from proof expath-split-given (previous step)

ispath(p, n, m, dirs, files) ⊦ ispath(p + q, n, dirs, files) ↔ ispath(q, m, dirs, files)

User applied rule case distinction

And obtained the following new goals

Proof step 4:
ispath(p, n, m, dirs, files), ispath(p + q, n, dirs, files) ⊦ ispath(q, m, dirs, files)
Proof step 9:
ispath(p, n, m, dirs, files), ispath(q, m, dirs, files) ⊦ ispath(p + q, n, dirs, files)

Rule argument

pos: right 1

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