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Proof step 11 from proof expath-split (previous step)

ispath(p, ino, m, dirs, files), ispath(q, m, dirs, files) ⊦ ∃ m. ispath(p + q, ino, m, dirs, files)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ ispath(p, n, dirs, files) ↔ (∃ m. ispath(p, n, m, dirs, files))
Proof step 13:
ispath(p, ino, m, dirs, files), ∃ m0. ispath(q, m, m0, dirs, files) ⊦ ∃ m. ispath(p + q, ino, m, dirs, files)

Rule argument

spec: <toplevel> name: expath seq: ⊦ ispath(p, n, dirs, files) ↔ (∃ m. ispath(p, n, m, dirs, files)) subst: [files, dirs, n, p] → [files, dirs, m, q] flags: <all paths>

Additional information

Used terms: files, dirs, m, q