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Proof step 14 from proof expath-split (previous step)

ispath(q, m, m0, dirs, files), ispath(p, ino, m, dirs, files) ⊦ ∃ m. ispath(p + q, ino, m, dirs, files)

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: m0 abort: F discard: F computed: F

Additional information

Used simplifier rules: path-trans: ⊦ ispath(p, n0, n1, dirs, files) ∧ ispath(q, n1, n2, dirs, files) → ispath(p + q, n0, n2, dirs, files);%a: ⊦ (p + p0) + p1 = p + p0 + p1; from specification list[path] Used terms: m0