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Proof step 10 from proof link-mod-dir-meta (previous step)

(m0 = m ⊃ dirs[m].meta:= md;dirs[m0]) = mkdir(m1, md0, m2, m3, entries), dirs[m0] = mkdir(m4, md1, m5, m6, entries0), m ∈ dirs, m0 ∈ dirs ⊦ str ∈ entries ∧ ino = entries[str] ↔ str ∈ entries0 ∧ ino = entries0[str]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
(m0 = m ⊃ dirs[m].meta:= md;mkdir(m4, md1, m5, m6, entries0)) = mkdir(m1, md0, m2, m3, entries), dirs[m0] = mkdir(m4, md1, m5, m6, entries0), m0 ∈ dirs, m ∈ dirs ⊦ str ∈ entries ∧ ino = entries[str] ↔ str ∈ entries0 ∧ ino = entries0[str]

Proof step 10 from proof link-mod-dir-meta (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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