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Proof step 5 from proof links-del-entry (previous step)

str ∈ entries, ino0 ∈ dirs ⊦ links(ino, dirs[ino0, mkdir(m, md, n0, n1, entries -- str)]) = (entries[str] = ino ⊃ links(entries[str], dirs[ino0, mkdir(m, md, n0, n1, entries)]) -- mklink(ino0, str) ;links(ino, dirs[ino0, mkdir(m, md, n0, n1, entries)]) )

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 6:
entries[str] = ino, ino0 ∈ dirs, str ∈ entries ⊦ links(ino, dirs[ino0, mkdir(m, md, n0, n1, entries -- str)]) = links(entries[str], dirs[ino0, mkdir(m, md, n0, n1, entries)]) -- mklink(ino0, str)
Proof step 15:
ino0 ∈ dirs, str ∈ entries ⊦ entries[str] = ino, links(ino, dirs[ino0, mkdir(m, md, n0, n1, entries -- str)]) = links(ino, dirs[ino0, mkdir(m, md, n0, n1, entries)])

Rule argument

pos: right 1

Proof step 5 from proof links-del-entry (previous step)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

Additional information