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Proof step 7 from proof links-dirs-union (previous step)

alink = mklink(m, str), dirs0 ⊥ dirs1 ⊦ (m ∈ dirs0 ∨ m ∈ dirs1) ∧ str ∈ (m ∈ dirs0 ⊃ dirs0[m];dirs1[m]).entries ∧ ino = (m ∈ dirs0 ⊃ dirs0[m];dirs1[m]).entries[str] ↔ alink ∈ links(ino, dirs0) ∪ links(ino, dirs1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
dirs0 ⊥ dirs1 ⊦ (m ∈ dirs0 ∨ m ∈ dirs1) ∧ str ∈ (m ∈ dirs0 ⊃ dirs0[m];dirs1[m]).entries ∧ ino = (m ∈ dirs0 ⊃ dirs0[m];dirs1[m]).entries[str] ↔ mklink(m, str) ∈ links(ino, dirs0) ∪ links(ino, dirs1)

Proof step 7 from proof links-dirs-union (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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