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Proof step 3 from proof meta-path (previous step)

ispath(p, n, m, dirs, files) ⊦ meta(p, n, dirs, files) = meta(ε, m, dirs, files)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: meta seq: ⊦ ispath(p, n, dirs, files) → meta(p, n, dirs, files) = (lookup(p, n, dirs, files) ∈ dirs ⊃ dirs[lookup(p, n, dirs, files)].meta ;files[lookup(p, n, dirs, files)].meta ) subst: [files, dirs, n, p] → [files, dirs, n, p] flags: <all paths>

Additional information

Used simplifier rules: isexpath: ⊦ ispath(p, n, m, dirs, files) → ispath(p, n, dirs, files); Used terms: files, dirs, n, p