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Proof step 4 from proof new-exists (previous step)

∀ n. n ∈ dirs ∨ n ∈ files → n < ino ⊦ ino = 0, ∃ ino. ino ≠ 0 ∧ ¬ ino ∈ dirs ∧ ¬ ino ∈ files

User applied rule exists right

And obtained the following new goals

Proof step 5:
∀ n. n ∈ dirs ∨ n ∈ files → n < ino ⊦ ino = 0, ∃ ino. ino ≠ 0 ∧ ¬ ino ∈ dirs ∧ ¬ ino ∈ files, ino ≠ 0 ∧ ¬ ino ∈ dirs ∧ ¬ ino ∈ files

Rule argument

pos: right 2 terms: ino abort: F discard: F computed: T

Additional information

Used terms: ino