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Proof step 4 from proof path-split (previous step)

dirs[n] = mkdir(m1, md, m2, m3, entries), name ∈ entries, n ∈ dirs, ∀ q, n, m, dirs, files. ispath(p0 + q, n, m, dirs, files) ↔ (∃ m0. ispath(p0, n, m0, dirs, files) ∧ ispath(q, m0, m, dirs, files)) ⊦ ispath(p0 + q, entries[name], m, dirs, files) ↔ (∃ m0. ispath(p0, entries[name], m0, dirs, files) ∧ ispath(q, m0, m, dirs, files))

User applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: q, entries[name], m, dirs, files abort: F discard: F computed: T

Additional information

Used terms: q, entries[name], m, dirs, files