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Proof step 8 from proof subdirs-modmeta (previous step)

(ino0 = ino ⊃ mkdir(m, md, n, n0, entries);dirs[ino0]) = mkdir(m1, md1, m2, m3, entries0), dirs[ino] = mkdir(m0, md0, n1, n2, entries), dirs[ino0] = mkdir(m4, md2, m5, m6, entries1), ino ∈ dirs, ino0 ∈ dirs ⊦ str ∈ entries0 ∧ entries0[str] ∈ dirs ↔ str ∈ entries1 ∧ entries1[str] ∈ dirs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
(ino0 = ino ⊃ mkdir(m, md, n, n0, entries);mkdir(m4, md2, m5, m6, entries1)) = mkdir(m1, md1, m2, m3, entries0), dirs[ino0] = mkdir(m4, md2, m5, m6, entries1), dirs[ino] = mkdir(m0, md0, n1, n2, entries), ino0 ∈ dirs, ino ∈ dirs ⊦ str ∈ entries0 ∧ entries0[str] ∈ dirs ↔ str ∈ entries1 ∧ entries1[str] ∈ dirs

Proof step 8 from proof subdirs-modmeta (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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