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Proof step 18 from proof truncate-empty (previous step)

files[ino0] = mkfile(m, md0, # links(ino0, dirs), content0), buf-opt = none, content = files[inode.ino].content, ino = inode.ino, inode = mkinode(ino0, md1, false, # links(ino0, dirs), 0, n), old_ino = min(n, inode.size), old_ino0 = inode.size % VFS_PAGE_SIZE, old_ino1 = 0, old_ino2 = 0, pageno = n / VFS_PAGE_SIZE, afs-cons(dirs, files), ino0 ∈ files ⊦ [if inode.size ≤ n ∧ old_ino0 ≠ 0 ∧ (pageno ∈ content ∨ buf-opt.some?) then {if buf-opt.some? then buf := buf-opt.buf else buf := files[ino].content[pageno]; buf := fill(buf, zero, old_ino0, VFS_PAGE_SIZE - old_ino0); content[pageno] := buf; buf-opt := some(buf)}; files[ino].content := content upto old_ino; let new_inode = inode in {new_inode.size := n; afs_inode_sync#(new_inode; dirs, files)}; inode := getinode(inode.ino, dirs, files); err := ESUCCESS; asynced := ?] (err = ESUCCESS → files[ino0].content.stream from n = σ⊥), VFS_PAGE_SIZE = 0

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

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