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Proof step 94 from proof truncate-empty (previous step)

files0[ino0] = mkfile(m, md0, # links(ino0, dirs), content0), files = files0[ino0, mkfile(m, md0, # links(ino0, dirs), content0 upto n)], ino = inode.ino, inode = mkinode(ino0, md1, false, # links(ino0, dirs), 0, n), inode0 = mkinode(ino0, md1, false, # links(ino0, dirs), 0, n), afs-cons(dirs, files0), ino0 ∈ files0 ⊦ [if ino ∈ files then {files[ino].size := inode.size; files[ino].meta := inode.meta} else if ino ∈ dirs then dirs[ino].meta := inode.meta; inode0 := (inode0.ino ∈ dirs ⊃ mkinode(inode0.ino, dirs[inode0.ino].meta, true, dirs[inode0.ino].nlink, dirs[inode0.ino].nsubdirs, dirs[inode0.ino].size) ;mkinode(inode0.ino, files[inode0.ino].meta, false, files[inode0.ino].nlink, 0, files[inode0.ino].size) ); err := ESUCCESS; asynced := ?] (err = ESUCCESS → files[ino0].content.stream from n = σ⊥), n % VFS_PAGE_SIZE ≠ 0 ∧ n / VFS_PAGE_SIZE ∈ content0

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

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