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Proof step 103 from proof truncate-same-iso (previous step)

files1[ino0] = mkfile(m2, md0, # links(ino0, dirs), content0), files = files1[ino0, mkfile(m2, md0, # links(ino0, dirs), content0 upto m2)], ino = inode.ino, inode = mkinode(ino0, md0, false, # links(ino0, dirs), 0, m2), inode0 = mkinode(ino0, md0, false, # links(ino0, dirs), 0, m2), afs-cons(dirs, files1), ino0 ∈ files1 ⊦ [asynced := ?] (files1 ~ files ∧ (⌊ESUCCESS⌋ ∨ ESUCCESS = ESUCCESS)), ino ∈ dirs, ino ∈ files, m2 % VFS_PAGE_SIZE ≠ 0 ∧ m2 / VFS_PAGE_SIZE ∈ content0

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ mkinode(m, md, boolvar, m0, m1, m2).ino = m; (s)% ⊦ ino ∈ files[ino0, af] ↔ ino ∈ files; (s)%⊦ afs-cons(dirs, files) ∧ ¬ ino ∈ dirs ∧ ¬ ino ∈ files → links(ino, dirs) = ∅; (s)% ⊦ # ∅ = 0; (s)