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Proof step 94 from proof truncate-same-iso (previous step)

(ino = ino0 ⊃ mkfile(m2, md0, # links(ino0, dirs), content0 upto m2);mkfile(m, md, # links(ino, dirs), content)) = mkfile(m0, md1, m1, content1), files1[ino] = mkfile(m, md, # links(ino, dirs), content), files1[ino0] = mkfile(m2, md0, # links(ino0, dirs), content0), afs-cons(dirs, files1), ino0 ∈ files1, ino ∈ files1 ⊦ m2 % VFS_PAGE_SIZE ≠ 0 ∧ m2 / VFS_PAGE_SIZE ∈ content0, m = m0 ∧ md = md1 ∧ # links(ino, dirs) = m1 ∧ content.stream to m0 = content1.stream to m0

User applied rule case distinction

And closed the goal!

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ mkfile(m, md, m0, content) = mkfile(m1, md0, m2, content0) ↔ m = m1 ∧ md = md0 ∧ m0 = m2 ∧ content = content0; (ws)% ⊦ (content upto m).stream to m = content.stream to m; (s)