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Proof step 1 from proof buf-stream-eq (conclusion)

⌜# buf⌝ = # σ ⊦ buf = σ.buf ↔ ⌜buf⌝ = σ

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⌜# σ.buf⌝ = # σ ⊦ ⌜σ.buf⌝ = σ

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜buf⌝ .buf = buf; (s)