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Proof step 2 from proof bufs-eq (previous step)

⊦ (σ to n).buf = (σ to m).buf ↔ n = m, # σ < ⌜m⌝ , # σ < ⌜n⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
(σ to n).buf = (σ to m).buf ⊦ n = m, # σ < ⌜n⌝ , # σ < ⌜m⌝

Rule argument

Additional information