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Proof step 4 from proof copy-stream-append (previous step)

# buf1 = n2 + n1 + m, n0 + m ≤ # buf0, n1 + m ≤ # buf1 ⊦ ⌜copy(buf0, n0, buf1, n1, m)⌝ = (⌜buf1⌝ to n1) + ((⌜buf0⌝ from n0) to m) + ((⌜buf1⌝ from n1 + m) to n2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# buf1 = n2 + n1 + m, n1 + m ≤ # buf1, n0 + m ≤ # buf0 ⊦ ⌜copy(buf0, n0, buf1, n1, m)⌝ = (⌜buf1⌝ to n1) + ((⌜buf0⌝ from n0) to m) + (⌜buf1⌝ from n1 + m)

Rule argument

Additional information

Used simplifier rules: append-assoc: ⊦ (σ0 + σ3) + σ4 = σ0 + σ3 + σ4; from specification stream[buffer-inf]% ⊦ # buf = n + m → (⌜buf⌝ from n) to m = ⌜buf⌝ from n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic