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Proof step 115 from proof fsync-inode-inv (previous step)

(m6 = m1 ⊃ mkfile(m4, md, # links(m1, dirs), content0);mkfile(m11, md4, # links(m6, dirs), content2)) = mkfile(m2, md3, m3, content1), files[m] = mkfile(m0, md0, # links(m, dirs), content), files[m1] = mkfile(m5, md1, # links(m1, dirs), content0), dirs[m1] = mkdir(m7, md2, m8, m9, entries), icache[m] = mkientry(true, mkinode(m1, md, false, # links(m1, dirs), 0, m4)), pcache[datakey(m6, m10)] = mkpentry(false, content2[m10]), files[m6] = mkfile(m11, md4, # links(m6, dirs), content2), afs-cons(dirs, files), afs-cons(dirs, files[m1, mkfile(m4, md, # links(m1, dirs), content0)]), synced(dirs, icache, pcache), m6 ∈ files, m1 ∈ files, m ∈ icache, m ∈ files, datakey(m6, m10) ∈ pcache, m10 ∈ content2, ∀ key0. key0 ∈ pcache → key0.data? ∧ # pcache[key0].page = VFS_PAGE_SIZE ∧ key0.ino ∈ files ∧ (¬ pcache[key0].dirty → key0.part ∈ files[key0.ino].content ∧ pcache[key0].page = files[key0.ino].content[key0.part]) ⊦ m10 ∈ content1 ∧ content2[m10] = content1[m10]

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: m6 = m1

Additional information

Used simplifier rules: ⊦ mkfile(m, md, m0, content) = mkfile(m1, md0, m2, content0) ↔ m = m1 ∧ md = md0 ∧ m0 = m2 ∧ content = content0; (ws) Used formulas: m6 = m1