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Proof step 112 from proof inv-create (previous step)

icache0[m1, mkientry(false, mkinode(m1, md1, true, # links(m1, dirs0), m4, m0 + 1))][ino0, mkientry(false, mkinode(ino0, md, false, 1, 0, 0))] [ino ] = mkientry(true, inode0), pcache[datakey(ino, n)] = mkpentry(boolvar, buf), dirs0[m1] = mkdir(m0, md2, # links(m1, dirs0), m4, entries1), icache0[ino] = mkientry(boolvar0, inode), afs-cons(dirs0[m1, mkdir(m0 + 1, md1, # links(m1, dirs0), m4, entries1[str, ino0])], (files0 ++ ino0)[ino0, mkfile(0, md, 1, ∅)]), afs-cons(dirs0, files0), synced(dirs0, icache0, pcache), m1 ∈ dirs0, ino ∈ dirs0, asynced1 → synced(files0, icache0, pcache), ino ∈ icache0 → ¬ boolvar0, datakey(ino, n) ∈ pcache → ¬ boolvar, ∀ n. datakey(ino, n) ∈ pcache → ¬ pcache[datakey(ino, n)].dirty, links(m1, dirs0) ≠ ∅ ∨ m1 = ROOT_INO, ino = m1 ∨ ino ∈ icache0 ⊦ ino0 = 0, str ∈ entries1, ino0 ∈ files0, ino0 ∈ dirs0

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: ino = ino0

Additional information

Used simplifier rules: ⊦ ino ≠ ino0 → icache[ino0, ie][ino] = icache[ino]; (s)% ⊦ icache[ino, ie][ino] = ie; (s)%⊦ mkientry(boolvar, inode) = mkientry(boolvar0, inode0) ↔ (boolvar ↔ boolvar0) ∧ inode = inode0; (ws) Used formulas: ino = ino0