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Proof step 106 from proof inv-evict (previous step)

# links(m, dirs) = 0, dirs[m] = mkdir(m0, md, 0, m2, entries), dirs[m3] = mkdir(m1, md0, # links(m3, dirs), m4, entries0), dcache[dentrykey(m3, str)] = mkdentry(str, entries0[str]), (dirs -- m)[m3] = mkdir(m5, md1, 0, m7, entries1), afs-cons(dirs, files), afs-cons(dirs -- m, files), synced(dirs, icache, pcache), str ∈ entries0, m ∈ dirs, dentrykey(m3, str) ∈ dcache, m3 ∈ dirs, asynced1 → synced(files, icache, pcache), ∀ key0. key0 ∈ dcache → key0.dentry? ∧ key0.name = dcache[key0].name ∧ key0.ino ∈ dirs ∧ (links(key0.ino, dirs) ≠ ∅ ∨ key0.ino = ROOT_INO) ∧ (dcache[key0].ino ∈ dirs ∨ dcache[key0].ino ∈ files) ∧ dcache[key0].name ∈ dirs[key0.ino].entries ∧ dcache[key0].ino = dirs[key0.ino].entries[dcache[key0].name] ∧ dcache[key0].dentry?, entries0[str] ∈ dirs ∨ entries0[str] ∈ files ⊦ # links(m3, dirs) = 0, entries0[str] = m, links(m3, dirs) = ∅, m = ROOT_INO, m3 = ROOT_INO, links(m3, dirs -- m) ≠ ∅ ∧ (entries0[str] ≠ m ∧ entries0[str] ∈ dirs ∨ entries0[str] ∈ files)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 107:
# links(m, dirs) = 0, dirs[m] = mkdir(m0, md, 0, m2, entries), dirs[m3] = mkdir(m1, md0, # links(m3, dirs), m4, entries0), dcache[dentrykey(m3, str)] = mkdentry(str, entries0[str]), (dirs -- m)[m3] = mkdir(m5, md1, 0, m7, entries1), afs-cons(dirs, files), afs-cons(dirs -- m, files), synced(dirs, icache, pcache), str ∈ entries0, m ∈ dirs, dentrykey(m3, str) ∈ dcache, m3 ∈ dirs, asynced1 → synced(files, icache, pcache), ∀ key0. key0 ∈ dcache → key0.dentry? ∧ key0.name = dcache[key0].name ∧ key0.ino ∈ dirs ∧ (links(key0.ino, dirs) ≠ ∅ ∨ key0.ino = ROOT_INO) ∧ (dcache[key0].ino ∈ dirs ∨ dcache[key0].ino ∈ files) ∧ dcache[key0].name ∈ dirs[key0.ino].entries ∧ dcache[key0].ino = dirs[key0.ino].entries[dcache[key0].name] ∧ dcache[key0].dentry?, entries0[str] ∈ dirs ∨ entries0[str] ∈ files ⊦ # links(m3, dirs) = 0, entries0[str] = m, links(m3, dirs) = ∅, m = ROOT_INO, m3 = ROOT_INO

Rule argument

Additional information

Used simplifier rules: ⊦ mkdir(m, md, m0, m1, entries).nlink = m0; (s)% ⊦ afs-cons(dirs, files) ∧ ino ∈ dirs → ¬ ino ∈ files; (s)% ⊦ ino ∈ dirs -- ino0 ↔ ino ≠ ino0 ∧ ino ∈ dirs; (s)%⊦ afs-cons(dirs, files) → ( links(ino, dirs) = ∅ ↔ (ino ∈ dirs → dirs[ino].nlink = 0) ∧ (ino ∈ files → files[ino].nlink = 0)); (ws)