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Proof step 49 from proof inv-evict (previous step)

# links(m, dirs) = 0, pcache[datakey(ino, n)] = mkpentry(boolvar, buf), dirs[m] = mkdir(m0, md, 0, m2, entries), icache[ino] = mkientry(boolvar0, inode), afs-cons(dirs -- m, files), afs-cons(dirs, files), synced(files, icache, pcache), ino ∈ files, m ∈ dirs, ino ∈ icache → ¬ boolvar0, ∀ n. datakey(ino, n) ∈ pcache → ¬ pcache[datakey(ino, n)].dirty ⊦ m = ROOT_INO, (ino ≠ m ∧ ino ∈ icache → ¬ boolvar0) ∧ (datakey(ino, n) ∈ pcache → ¬ boolvar)

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Proof step 50:
# links(m, dirs) = 0, icache[ino] = mkientry(boolvar0, inode), dirs[m] = mkdir(m0, md, 0, m2, entries), pcache[datakey(ino, n)] = mkpentry(boolvar, buf), afs-cons(dirs, files), afs-cons(dirs -- m, files), synced(files, icache, pcache), m ∈ dirs, ino ∈ files, ino ∈ icache → ¬ boolvar0, ∀ n. datakey(ino, n) ∈ pcache → ¬ pcache[datakey(ino, n)].dirty ⊦ ino = m, m = ROOT_INO, (ino ≠ m ∧ ino ∈ icache → ¬ boolvar0) ∧ (datakey(ino, n) ∈ pcache → ¬ boolvar)

Rule argument

fma: ino = m

Additional information

Used simplifier rules: ⊦ afs-cons(dirs, files) ∧ ino ∈ dirs → ¬ ino ∈ files; (s) Used formulas: ino = m