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Proof step 34 from proof inv-iget (previous step)

(ino ∈ dirs ⊃ mkinode(ino, dirs[ino].meta, true, dirs[ino].nlink, dirs[ino].nsubdirs, dirs[ino].size) ;mkinode(ino, files[ino].meta, false, files[ino].nlink, 0, files[ino].size) ) = mkinode(m, md, boolvar, m0, m1, m2), afs-cons(dirs, files), icache-cons(icache[m, mkientry(false, mkinode(m, md, boolvar, m0, m1, m2))], dirs, files), icache-cons(icache, dirs, files), synced(dirs, icache, pcache), asynced2 → synced(files, icache, pcache), ino ∈ dirs ∨ ino ∈ files ⊦ ino ∈ icache, synced(dirs, icache[m, mkientry(false, mkinode(m, md, boolvar, m0, m1, m2))], pcache) ∧ (asynced2 → synced(files, icache[m, mkientry(false, mkinode(m, md, boolvar, m0, m1, m2))], pcache))

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: ino ∈ dirs

Additional information

Used simplifier rules: ⊦ mkinode(m, md, boolvar, m0, m1, m2) = mkinode(m3, md0, boolvar0, m4, m5, m6) ↔ m = m3 ∧ md = md0 ∧ (boolvar ↔ boolvar0) ∧ m0 = m4 ∧ m1 = m5 ∧ m2 = m6; (ws)%⊦ ¬ ino ∈ icache → ( synced(dirs, icache[ino, mkientry(false, inode)], pcache) ↔ synced(dirs, icache, pcache)); (s)%⊦ ¬ ino ∈ icache → ( synced(files, icache[ino, mkientry(false, inode)], pcache) ↔ synced(files, icache, pcache)); (s) Used formulas: ino ∈ dirs