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Proof step 157 from proof inv-unlink (previous step)

# links(entries0[str], dirs0) = m2 + 1, (m5 = entries0[str] ⊃ mkfile(m3, md0, m2, content0);mkfile(m9, md4, # links(m5, dirs0), content1)) = mkfile(m, md, m4, content), files0[entries0[str]] = mkfile(m1, md1, m2 + 1, content0), dirs0[m0] = mkdir(m8 + 1, md2, # links(m0, dirs0), m7, entries0), pcache[datakey(m5, m6)] = mkpentry(false, content1[m6]), files0[m5] = mkfile(m9, md4, # links(m5, dirs0), content1), afs-cons(dirs0[m0, mkdir(m8, md3, # links(m0, dirs0), m7, entries0 -- str)], files0[entries0[str], mkfile(m3, md0, m2, content0)]), afs-cons(dirs0, files0), synced(dirs0, icache0, pcache), m5 ∈ files0, m0 ∈ dirs0, entries0[str] ∈ files0, str ∈ entries0, datakey(m5, m6) ∈ pcache, m6 ∈ content1, asynced1 → synced(files0, icache0, pcache), ∀ key0. key0 ∈ pcache → key0.data? ∧ # pcache[key0].page = VFS_PAGE_SIZE ∧ key0.ino ∈ files0 ∧ (¬ pcache[key0].dirty → key0.part ∈ files0[key0.ino].content ∧ pcache[key0].page = files0[key0.ino].content[key0.part]), links(m0, dirs0) ≠ ∅ ∨ m0 = ROOT_INO ⊦ m6 ∈ content ∧ content1[m6] = content[m6]

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: m5 = entries0[str]

Additional information

Used simplifier rules: ⊦ mkfile(m, md, m0, content) = mkfile(m1, md0, m2, content0) ↔ m = m1 ∧ md = md0 ∧ m0 = m2 ∧ content = content0; (ws) Used formulas: m5 = entries0[str]