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Proof step 383 from proof inv-write_inode (previous step)

(m3 = m ⊃ (files[m].meta:= md).size:= m2;mkfile(m5, md1, # links(m3, dirs), content0)) = mkfile(m0, md0, m1, content), pcache[datakey(m3, m4)] = mkpentry(false, content0[m4]), files[m3] = mkfile(m5, md1, # links(m3, dirs), content0), afs-cons(dirs, files[m, (files[m].meta:= md).size:= m2]), afs-cons(dirs, files), synced(dirs, icache, pcache), synced(files, icache, pcache), m3 ∈ files, m ∈ files, datakey(m3, m4) ∈ pcache, m4 ∈ content0, ∀ key0. key0 ∈ pcache → key0.data? ∧ # pcache[key0].page = VFS_PAGE_SIZE ∧ key0.ino ∈ files ∧ (¬ pcache[key0].dirty → key0.part ∈ files[key0.ino].content ∧ pcache[key0].page = files[key0.ino].content[key0.part]) ⊦ m ∈ icache, m4 ∈ content ∧ content0[m4] = content[m4]

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: m3 = m

Additional information

Used simplifier rules: ⊦ mkfile(m, md, m0, content) = mkfile(m1, md0, m2, content0) ↔ m = m1 ∧ md = md0 ∧ m0 = m2 ∧ content = content0; (ws)% ⊦ mkfile(m, md, m0, content).meta:= md0 = mkfile(m, md0, m0, content); (s)% ⊦ mkfile(m, md, m0, content).size:= m1 = mkfile(m1, md, m0, content); (s) Used formulas: m3 = m