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Proof step 13 from proof synced-files-update-clean-inode (previous step)

icache[ino] = mkientry(false, inode1), pcache[datakey(ino, n)] = mkpentry(true, buf), datakey(ino, n) ∈ pcache, ino ∈ icache, ino ∈ files, ∀ n. datakey(ino, n) ∈ pcache → ¬ pcache[datakey(ino, n)].dirty, ∀ ino0. ino0 ∈ files → (ino0 ∈ icache[ino, mkientry(false, inode)] → ¬ icache[ino, mkientry(false, inode)][ino0].dirty) ∧ (∀ n. datakey(ino0, n) ∈ pcache → ¬ pcache[datakey(ino0, n)].dirty) ⊦

User applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ mkpentry(boolvar, buf).dirty ↔ boolvar; (s) Used terms: n