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Proof step 52 from proof fsync-inode-overwrite (previous step)

files0[m] = mkfile(m0, md0, m1, content), icache[m] = mkientry(true, mkinode(m2, md, true, m4, m5, m3)), dirs[m2] = mkdir(m3, md1, m4, m5, entries), m2 ∈ dirs, m ∈ files0, m ∈ icache, ∀ ino. ino ∈ icache → icache[ino].inode.ino = ino ∧ (icache[ino].dirty ⊃ icache[ino].inode.ino ∈ files0 ∧ icache[ino].inode.nlink = files0[icache[ino].inode.ino].nlink ∧ icache[ino].inode.nsubdirs = 0 ∧ ¬ icache[ino].inode.directory ; (ino ∈ dirs ∨ ino ∈ files0) ∧ icache[ino].inode = (icache[ino].inode.ino ∈ dirs ⊃ mkinode (icache[ino].inode.ino, dirs[icache[ino].inode.ino].meta, true, dirs[icache[ino].inode.ino].nlink, dirs[icache[ino].inode.ino].nsubdirs, dirs[icache[ino].inode.ino].size) ;mkinode (icache[ino].inode.ino, files0[icache[ino].inode.ino].meta, false, files0[icache[ino].inode.ino].nlink, 0, files0[icache[ino].inode.ino].size) ) ) ⊦ files0[m2] = (files0 ⊕ icache)[m2]

User applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: m abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ mkientry(boolvar, inode).inode = inode; (s)% ⊦ mkinode(m, md, boolvar, m0, m1, m2).ino = m; (s)% ⊦ mkientry(boolvar, inode).dirty ↔ boolvar; (s)% ⊦ mkinode(m, md, boolvar, m0, m1, m2).nlink = m0; (s)% ⊦ mkfile(m, md, m0, content).nlink = m0; (s)% ⊦ mkinode(m, md, boolvar, m0, m1, m2).nsubdirs = m1; (s)% ⊦ mkinode(m, md, boolvar, m0, m1, m2).directory ↔ boolvar; (s) Used terms: m