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Proof step 366 from proof fsync-pages-keep-abs (previous step)

# buf1 = VFS_PAGE_SIZE, icache[m] = mkientry(boolvar, mkinode(m3, md0, false, m4, m5, m6)), files0[m] = mkfile(m0, md, m1, content), files1[m] = mkfile(m9, md2, m10, content1), pcache0[datakey(m, n)] = mkpentry(boolvar0, buf1), pcache[datakey(m, n)] = mkpentry(true, buf1), n * VFS_PAGE_SIZE < m2, pcache-cons(pcache0, dirs, files1), n ∈ content[n, buf1] ⊕ mkcontent(m, pcache[datakey(m, n), mkpentry(false, buf1)]), datakey(m, n) ∈ pcache0, m ∈ files1, m ∈ files0, m ∈ icache, n ∈ content ⊕ mkcontent(m, pcache), n ∈ content1 ⊕ mkcontent(m, pcache0), datakey(m, n) ∈ pcache, ∀ ino0. (ino0 ∈ files0 ↔ ino0 ∈ files1) ∧ (ino0 ∈ files0 → ((files0 ⊕ pcache) ⊕ icache)[ino0] = ((files1 ⊕ pcache0) ⊕ icache)[ino0]) ⊦ (content1 ⊕ mkcontent(m, pcache0))[n] = buf1

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: n ∈ mkcontent(m, pcache0)

Additional information

Used simplifier rules: ⊦ ¬ n ∈ content1 → (content0 ⊕ content1)[n] = content0[n]; (s)% ⊦ n ∈ content0 ⊕ content1 ↔ n ∈ content0 ∨ n ∈ content1; (ws)% ⊦ n ∈ mkcontent(ino, pcache) ↔ datakey(ino, n) ∈ pcache; (s)% ⊦ n ∈ content1 → (content0 ⊕ content1)[n] = content1[n]; (s)% ⊦ mkcontent(ino, pcache)[n] = pcache[datakey(ino, n)].page; (s)% ⊦ mkpentry(boolvar, buf).page = buf; (s) Used formulas: n ∈ mkcontent(m, pcache0)