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Proof step 61 from proof initialization (previous step)

⌊err0⌋ ⊦ ∃ dirs, files, asynced. ⟨fail#(; ; err)⟩ (dirs0 = dirs ∧ files0 = files ∧ (asynced1 ↔ asynced) ∧ err0 = err)

User applied rule exists right

And obtained the following new goals

Proof step 62:
⌊err0⌋ ⊦ ⟨fail#(; ; err)⟩ (dirs0 = dirs0 ∧ files0 = files0 ∧ (asynced1 ↔ asynced1) ∧ err0 = err)

Rule argument

pos: right 1 terms: dirs0, files0, asynced1 abort: F discard: T computed: F

Additional information

Used terms: dirs0, files0, asynced1