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Proof step 5 from proof in-evict-other (previous step)

∀ ino, pageno, ino0. (datakey(ino, pageno) ∈ evict(ino0, pcache0) ↔ datakey(ino, pageno) ∈ pcache0) ∨ ino = ino0 ⊦ datakey(ino, pageno) ∈ evict(ino0, pcache0) ↔ datakey(ino, pageno) ∈ pcache0[inodekey(ino1), pe], ino = ino0

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: ino, pageno, ino0 abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ key ∈ pcache[key0, pe] ↔ key = key0 ∨ key ∈ pcache; (ws)% ⊦ inodekey(m) ≠ datakey(m0, m1); (s) Used terms: ino, pageno, ino0