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Proof step 3 from proof abs-dirs-trunc (previous step)

⊦ adr ∈ ri, (inodekey(ino) ∈ ri → (fs[ri[inodekey(ino)]].directory ↔ fs[adr, truncnode(key, n)][ri[inodekey(ino)]].directory)) ∧ ( inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].directory → mkdir (fs[ri[inodekey(ino)]].size, fs[ri[inodekey(ino)]].meta, fs[ri[inodekey(ino)]].nlink, fs[ri[inodekey(ino)]].nsubdirs, abs-children(ino, fs, ri)) = mkdir (fs[adr, truncnode(key, n)][ri[inodekey(ino)]].size, fs[adr, truncnode(key, n)][ri[inodekey(ino)]].meta, fs[adr, truncnode(key, n)][ri[inodekey(ino)]].nlink, fs[adr, truncnode(key, n)][ri[inodekey(ino)]].nsubdirs, abs-children(ino, fs[adr, truncnode(key, n)], ri)))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 2

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