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Proof step 6 from proof abs-keys-orphans-add (previous step)

abs-keys(ro) = abs-keys(orphans(fs, ri)) ++ n, ro.inodes? ⊦ key ∈ ro ↔ key = inodekey(n) ∨ key.inode? ∧ key ∈ ri ∧ fs[ri[key]].nlink = 0 ∧ key.ino ≠ ROOT_INO

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Proof step 7:
abs-keys(ro) = abs-keys(orphans(fs, ri)) ++ n, key.inode?, ro.inodes? ⊦ key ∈ ro ↔ key = inodekey(n) ∨ key.inode? ∧ key ∈ ri ∧ fs[ri[key]].nlink = 0 ∧ key.ino ≠ ROOT_INO

Rule argument

fma: key.inode?

Additional information

Used simplifier rules: ⊦ key ∈ ks ∧ ks.inodes? → key.inode?; (ss)% ⊦ inodekey(m).inode?; (s) Used formulas: key.inode?