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Proof step 10 from proof abs-keys-orphans-add2 (previous step)

key.inode?, ∀ ino. inodekey(ino) ∈ ri0 ∧ fs0[ri0[inodekey(ino)]].nlink = 0 ∧ ino ≠ ROOT_INO ↔ ino = n ∨ inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].nlink = 0 ∧ ino ≠ ROOT_INO ⊦ key.inode? ∧ key ∈ ri0 ∧ fs0[ri0[key]].nlink = 0 ∧ key.ino ≠ ROOT_INO ↔ key = inodekey(n) ∨ key.inode? ∧ key ∈ ri ∧ fs[ri[key]].nlink = 0 ∧ key.ino ≠ ROOT_INO

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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