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Proof step 7 from proof abs-keys-orphans2 (previous step)

abs-keys(orphans(fs0, ri0)) = abs-keys(orphans(fs, ri)), key = inodekey(m), key.inode? ⊦ key ∈ ri0 ∧ fs0[ri0[key]].nlink = 0 ↔ key ∈ ri ∧ fs[ri[key]].nlink = 0, m = ROOT_INO

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
abs-keys(orphans(fs0, ri0)) = abs-keys(orphans(fs, ri)) ⊦ inodekey(m) ∈ ri0 ∧ fs0[ri0[inodekey(m)]].nlink = 0 ↔ inodekey(m) ∈ ri ∧ fs[ri[inodekey(m)]].nlink = 0, m = ROOT_INO

Rule argument

Additional information

Used simplifier rules: ⊦ inodekey(m).inode?; (s)